In article <87zk3fc3wv.fsf@merciadriluca-station.MERCIADRILUCA>,
Merciadri Luca <Luca.Merciadri@student.ulg.ac.be> wrote:
> -----BEGIN PGP SIGNED MESSAGE-----
> Hash: SHA1
>
> Hello,
>
> I've got a string, say str. This string contains only digits; for
> example, 1456823.
>
> I also have two vectors:
> 1) a row vector whose elements are the ones that need to be replaced
> 2) a row vector whose elements are the ones that need to replace.
>
> For example, if I want to replace every `4' and `5' by `7' and `4',
> respectively, in the original string, that means '1456823' becomes
> '1746823'.
Just use a lookup table:
lut = char(1:255);
lut('45') = '74'; % the substitutions to be made
lut('1456823')
ans =
1746823
--
Doug Schwarz
dmschwarz&ieee,org
Make obvious changes to get real email address.
Merciadri Luca <Luca.Merciadri@student.ulg.ac.be> wrote:
> -----BEGIN PGP SIGNED MESSAGE-----
> Hash: SHA1
>
> Hello,
>
> I've got a string, say str. This string contains only digits; for
> example, 1456823.
>
> I also have two vectors:
> 1) a row vector whose elements are the ones that need to be replaced
> 2) a row vector whose elements are the ones that need to replace.
>
> For example, if I want to replace every `4' and `5' by `7' and `4',
> respectively, in the original string, that means '1456823' becomes
> '1746823'.
Just use a lookup table:
lut = char(1:255);
lut('45') = '74'; % the substitutions to be made
lut('1456823')
ans =
1746823
--
Doug Schwarz
dmschwarz&ieee,org
Make obvious changes to get real email address.